The molar mass of glucose is 180 grams per mole (g/mol). which of the following procedures should you carry out to make a 1 m solution of glucose?
a. dissolve 180 g of glucose in .8 l of water, then bring the volume to 1l
b. dissolve 180 g of glucose in 180 g of water then bring the volume to 1l
c. dissolve 1 g of glucose in .1 l of water then bring th volume to 1l
d. dissolve 180 milligrams (mg) of glucose in 1 l of water

the correct answer would be d. hope this !

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied