Chemistry, 24.08.2019 01:30 valdezavery1373

The elementary reaction a+b→2c + d the reactor is initially charged with cbo/cad-3.0, and cad-0.01 movl, calculate the value of reaction rate constant, k after 10 min of reaction when the conversion of a is 50 %

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Answer from: zitterkoph

Explanation:

As the given reaction is as follows.

$A + B \rightarrow 2C + D$

at t = 0 $C_{Ao}$ $3C_{Ao}$ 0 0

at t = t' $C_{Ao} - C_{Ao}X_{Ao}$ $3C_{Ao} - C_{Ao}X_{A}$ $2X_{A}C_{Ao}$ $C_{Ao}X_{A}$

$-r_{A}$ = $\frac{dC_{A}}{dt}$ = $kC_{A}C_{B}$

= $kC_{Ao}(1 - X_{A})C_{Ao}(3 - X_{A})$

= $kC^{2}_{Ao}(1 - X_{A})(3 - X_{A})$

$\frac{dC_{Ao}(1 - X_{A})}{dt}$ = $kC^{2}_{Ao}(1 - X_{A})(3 - X_{A})$

$-C_{Ao}\frac{dX_{A}}{dt}$ = kC^{2}_{Ao} (1 - X_{A})(3 - X_{A})[/tex]

$\int_{0}^{0.5}\frac{dX_{A}}{(1 - X_{A})(3 - X_{A})}$ = $kC_{Ao}\int_{0}^{10 min}dt$

$\int_{0}^{0.5}[\frac{1}{2(1 - X_{A})} - \frac{1}{2(3 - X_{A})}] dX_{A}$ = $kC_{Ao} \times (10 - 0)$

$\frac{1}{2}[-ln (1 - X_{A})]^{0.5}_{0} + \frac{1}{2}[ln(3 - X_{A})]^{0.5}_{0}$ = $kC_{Ao} \times 10$

$\frac{1}{2}[ln 1 - ln 0.5]^{0.5}_{0} + \frac{1}{2} \times (\frac{2.5}{3})$ = $kC_{Ao} \times 10$

0.2554 = $kC_{Ao} \times 10$

Given, $C_{Ao}$ = 0.01 mol/L

k = $\frac{0.2554 L mol^{-1} min^{-1}}{0.01 \times 10}$

= 2.554 $L mol^{-1} min^{-1}$

Thus, we can conclude that value of given reaction rate constant is 2.554 $L mol^{-1} min^{-1}$ .

Answer from: Quest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

Electrons are transferred from atoms of to atoms of this transfer makes the sodium atoms and the

Answer from: Quest

the food using pesticides in the future will harm you by giving you diseases like cancer or something since they have things that we should not eat in it like chemicals or pesticides. that is why organic food is more expensive because they take the time to make it right and healthy for you to eat.

explanation: