Astock solution is 28.2 percent ammonia (nh3) by mass, and the solution has a density of 0.8990 grams per milliliter. what volume, in milliliters, of this stock solution is required to prepare 600 milliliters of a 0.500 molar ammonia solution?

Explanation:

Assume that the volume of the stock solution is 1 L.

1. Mass of  stock solution

2.Mass of NH₃

3. Moles of NH₃

4. Molar concentration of stock solution

5. Volume of stock needed for dilution

Now that you know the concentration of the stock solution, you can use the dilution formula .

to calculate the volume of stock solution.

Data:

c₁ = 14.89   mol·L⁻¹; V₁ = ?

c₂ = 0.500 mol·L⁻¹; V₂ = 600 mL

Calculations:

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question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)