Astock solution is 28.2 percent ammonia (nh3) by mass, and the solution has a density of 0.8990 grams per milliliter. what volume, in milliliters, of this stock solution is required to prepare 600 milliliters of a 0.500 molar ammonia solution?

Explanation:

Assume that the volume of the stock solution is 1 L.

1. Mass of  stock solution

2.Mass of NH₃

3. Moles of NH₃

4. Molar concentration of stock solution

5. Volume of stock needed for dilution

Now that you know the concentration of the stock solution, you can use the dilution formula .

to calculate the volume of stock solution.

Data:

c₁ = 14.89   mol·L⁻¹; V₁ = ?

c₂ = 0.500 mol·L⁻¹; V₂ = 600 mL

Calculations:

dynamic equilibrium is the answer.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.