What is the energy released in this β − β − nuclear reaction 40 19 k → 40 20 c a + 0 − 1 e 19 40 k → 20 40 c a + − 1 0 e ? (the atomic mass of 40 k 40 k is 39.963998 u and that of 40 c a 40 c a is 39.962591 u)

The energy released in the given nuclear reaction is 1.3106 MeV.

Explanation:

For the given nuclear reaction:

We are given:

Mass of = 39.963998 u

Mass of = 39.962591 u

To calculate the mass defect, we use the equation:

Putting values in above equation, we get:

To calculate the energy released, we use the equation:

   (Conversion factor:    )

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

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