The boiling point of bromine is 59 °c. which of the following best predicts the boiling point of iodine monochloride, a polar compound?
higher than 59 °c because dipole-dipole interactions in iodine monochloride are stronger than dispersion forces in bromine.
lower than 59 °c because ionic bonding in bromine is stronger than covalent bonding in iodine monochloride.
lower than 59 °c because dipole-dipole interactions in iodine monochloride are weaker than in bromine.
higher than 59 °c because ionic bonding in iodine monochloride is stronger than h-bonding in bromine.

Higher than 59 °C because dipole-dipole interactions in iodine monochloride are stronger than dispersion forces in bromine.

Explanation:

Intermolecular forces are broadly classified into four types:

1) Ionic

2) Hydrogen bonding

3) Dipole-dipole

4) London dispersion

The strongest is the ionic interaction while the weakest are the dispersion forces. Bromine () is a non-polar molecule due to the absence of a permanent dipole. The only force of attraction in non-polar molecules are the weak dispersion forces.

In contrast iodine monochloride () is a polar molecule which are held together dipole-dipole forces that are stronger than the London dispersion forces.

Hence, the boiling point of () would be higher than that of  ()

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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