A8390 g/hr stream of liquid methyl alcohol, also called methanol, (ch_3oh) at 6.20 atm and 24.0 degree c was held at constant pressure, vaporized and brought to 337.0 degree c. at what rate must heat be supplied to this system? assume that methyl alcohol vapor behaves ideally for the temperature range and pressure given.

heat must be supplied to the system at a rate of 6670.22 KJ/h

Explanation:

m = 8390 g/h * ( Kg / 1000g )

⇒ m = 8.39 Kg/h

P1 = P2 = 6,20 atm constant pressure

T1 = 24°C = 297 K

T2 = 337.0°C = 610 K

⇒ ΔT = 610 - 297 = 313 K

Q = ?

starting from first law at constant pressure:

∴ Cp (24°C) = 2,54 KJ / Kg°Kengineering toolbox CH3OH

⇒ Q = ( 8.39 Kg/h ) * ( 2.54 KJ / Kg K ) * ( 313 K )

⇒ Q = 6670.22 KJ/h

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

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