It takes 2,267 joules of heat to raise the temperature of a 44.5 gram sample of a metal from 33.9°c to 288.3°c. what is the heat capacity of the metal?

Explanation:

The formula for the amount heat q absorbed by a substance is

q = mcΔT

where

 m = the mass of the substance

  C = the specific heat capacity of the material

ΔT = the temperature change

Data:

 q = 2267 J

m = 44.5 g

T₁ = 33.9 °C

T₂ = 288.3 °C

Calculations:

ΔT = (288.3 - 33.9) °C = 254.4 °C

answer; ///i do believe that the correct answer is (b); ///particle composed of two or more atoms bonded together;

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