Aparticular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 14.3 gal tank (1us gal=3.78l)? express your answer to three significant figures and include the appropriate units.

the tank will be filled with 39,8*10³g of gasoline

Explanation:

Given that the units for density are g/mL, the first step is to know the volume of tank expressed in L.using the value given in the question  

Tank volume (L)= 14.3 gal* (3.78L/1gal)= 54.054 L

Now, we need this volume expressed in mL, Remember 1L = 1000mL, so

Tank volume (mL)= 54.054L * (1000mL/ 1L) = 54054mL

Now, we can use the density to get the answer.

gasoline (g) = 54054mL* 0.737g/mL =  39837g

There are 5 significant figures in 39837, for that reason we need to reduce this expression to get only 3 significant figures, but without altering the result.

If we use scientific notation, we could write 39,837*10³g of gasoline, and finally we rounded this number to get just 3 significant figures, and we get 39.8*10³g of gasoline