Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . suppose 1.74 g of butane is mixed with 11. g of oxygen. calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. be sure your answer has the correct number of significant digits.

Answer : The mass of produced will be, 5.3 grams.

Explanation : Given,

Mass of = 1.74 g

Mass of = 11 g

Molar mass of = 58 g/mole

Molar mass of = 32 g/mole

Molar mass of = 44 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react with 13 mole of

So, 0.03 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of .

As, 2 moles of react to give 8 moles of

So, 0.03 moles of react to give moles of

Now we have to calculate the mass of .

Therefore, the mass of produced will be, 5.3 grams.

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for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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