Carbon-14 has a half-life of 5,730 years. if scientists discover a mummified cro-magnon specimen, they will first want to determine its age. when examining a sample from the bone remains, the scientists discover the specimen is composed of 25% carbon-14 and 75% nitrogen-14. how old is this specimen?

the specimen has 11460 years old

Explanation:

if the live sample has as initial amount of Yo C14, the dead sample will have 0.25Yo of C14.

the rate of decay of radiactive matter over time is

∴ Y(t) = 0.25Yo;  T = 5730

⇒ 0.25Yo = Yo * e (( - t * Ln2 ) / 5730 )

⇒ 0.25 = e (( - t * Ln2 ) / 5730 )

⇒ Ln(0.25) = ( -  t * Ln2 ) / 5730

⇒ - 7943.466 = - t * Ln2

⇒ 7943.466 / Ln2 = t

⇒ t = 11460 year

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