What is the percentage increased in the volume of a gas when the pressure is reduced to half at constant temperature?

100% increase.

Explanation:

At constant temperature we have the relation

P1V1 = P2V2    where P and V are pressures and volumes, so here we have, say

P1 = 10, P2 = 1/2* 10 = 5  , V1 = 10 , V2 = ?

10 * 10 = 5 * V2

V2 = 100/5 = 20.

The original volume was 10  so the volume has doubled.

b. th3 n4zc4 pl4t3 15 c0nv3rg1ng w1th the s0uth 4m3ric4n pl4t3.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.