Lexan is a plastic used to make compact discs, eyeglass lenses, and bullet-proof glass. one of the compounds used to make lexan is phosgene (cocly), an extremely poisonous gas. phosgene decomposes by the reaction coch(o) co(g)+cla (9) for which k, 6.8 x 10- at 100°c. if pure phosgene at an initial pressure of 4 8 atm decomposes, calculate the equilibrium pressures of all species partial pressure of coch- partial pressure of co- partial pressure of cla atm atm atm

p[CO] = 1.81*10⁻⁴ atm

p[Cl2] =  1.81*10⁻⁴ atm

p[COCl2]  = 4.8 atm

Explanation:

Given:

Pressure of phosgene, COCl2 = 4.8 atm

Kp = 6.8*10^-9

To determine:

The equilibrium partial pressures of COCl2, Cl2, CO

Calculation:

Set-up an ICE table for the given reaction:

I                 4.8                 0   0

C              -x                    +x   +x

E              (4.8-x)              x     x          

The equilibrium partial pressures are:

p[CO] = x = 1.81*10⁻⁴ atm

p[Cl2] = x = 1.81*10⁻⁴ atm

p[COCl2] = 4.8-x =4.8- 1.81*10⁻⁴ atm = 4.8 atm

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :