Consider the reaction of c3h8 with o2 to form co2 and h2o. if 5.11 g o2 is reacted with excess c3h8 and 3.35 g of co2 is ultimately isolated, what is the percent yield for the reaction? percent yield = %

Answer : The percent yield of the reaction is, 79.8 %

Explanation :  Given,

Mass of = 5.11 g

Molar mass of = 32 g/mole

Molar mass of = 44 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of .

The balanced chemical reaction will be,

From the balanced reaction, we conclude that

As, 5 moles of react to give 3 moles of

So, 0.159 moles of react to give moles of

Now we have to calculate the mass of

The theoretical yield of  = 4.1976 g

The actual yield of  = 3.35 g

Now we have to calculate the percent yield of

Therefore, the percent yield of the reaction is, 79.8 %

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).