At a particular temperature, k 5.0 x 10-6 for the reaction 2co2(9) 2co(9) +02(9) if 3.0 moles of co2 is initially placed into a 5.0-l vessel, calculate the equilibrium concentrations of all species. co2] co] o2l [02]-

Answer : The concentration of at equilibrium will be, 0.598 M, 0.00216 M and 0.00108 M respectively.

Explanation : Given,

Equilibrium constant =

tex]\text{Concentration of }CO_2=\frac{\text{Moles of }CO_2}{\text{Volume of solution}}=\frac{3.0mole}{5.0L}=0.6mole=0.6M[/tex]

The balanced equilibrium reaction is,

Initial conc.     0.6 M                 0             0

At eqm.        (0.6-2x) M          2x M         x M

The expression of equilibrium constant for the reaction will be:

Now put all the values in this expression, we get :

By solving the term 'x', we get:

Concentration of at equilibrium =

Concentration of at equilibrium =

Concentration of at equilibrium =

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2