Chemistry, 08.08.2019 06:10 david1236544
what is the calculated value of the cell potential at 298k for an electrochemical cell with the following reaction, when the cu2+ concentration is 2.32×10-4 m and the mn2+ concentration is 1.04 m ?
cu2+(aq) + mn(s) cu(s) + mn2+(aq)
the cell reaction as written above is spontaneous for the concentrations given: (true/false)
Answers: 2
of the reaction, we use the equation:
![E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}](/tpl/images/0173/1697/70482.png)
= electrode potential of the cell = ?V![[Cu^{2+}]=2.32\times 10^{-4}M](/tpl/images/0173/1697/f12ce.png)
![[Mn^{2+}]=1.04M](/tpl/images/0173/1697/250ae.png)
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