A15.0 g metal sample at 25.0 °c has 250 j of heat added to it. the specific heat of the metal is 0.128 j/g.°c. what is the final temperature?

The final temperature is

Explanation:

To calculate the final temperature, we use the equation:

where,

Q = heat absorbed = 250 J

m = Mass of the substance = 15 g

c = specific heat capacity of water = 0.128 J/g.°C

= change in temperature =

Putting values in above equation, we get:

Hence, the final temperature is

idk what the question is about