How would the calculated value of ksp be affected by the accidental and unknowing collection of solid lead(ii) chloride via pipet in the gibb’s free energy experiment? this would not affect the calculated value of ksp. the calculated value of ksp would be too small. the calculated value of ksp would be too big.

Explanation:

It is known that relation between Gibb's free energy and equilibrium or reaction quotient is as follows.

                 ..... (1)

At equilibrium, = 0. Also, Q = K this means that reaction is at equilibrium.

Therefore, formula in equation (1) will become as follows.

                     ....... (2)

It is known that for a sparingly soluble salt, K =

Thus, equation (2) will become as follows.

                 ....... (3)

So, when value of increases then there will be decrease in the value of according to equation (3).

Hence, we can conclude that the calculated value of would be too big.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

sure im new too!

explanation: