Phosphorus pentachloride reacts with water to give phosphoric acid and hydrogen chloride according to the following equation:
pcl5 + 4h20 → h3po4 + 5hci
in one experiment, 0.287 mol of pcl5 was slowly added to 3.84 mol of water.
how many grams of hcl were formed in the reaction?

52.4 grams

Explanation:

The two reactants PCl5 and H2O, must occur in a 1:4 ratio, so that tells us, that we need 4 times more H₂O than phosphorus pentachloride.

0.287 moles PCl5 multiplied by 4 equal 1.15 moles H2O. That tell sus that 1.15 moles H2O is needed.

Because we have 3.84 moles H2O, the PCL5 is the limiting reactant.

0.287 mol PCl₅ x (5 mol HCl divided by 1 mol  of PCl₅) x ( 36.5g HCl divided by moles of HCl) = 52.4 g of HCl is formed

(Hopefully this helps!)