Chemistry, 31.07.2019 23:10 aubriebv2020
The solubility of cd(oh)2 can be increased through formation of the complex ion cdbr2−4 (kf=5×103). if solid cd(oh)2 is added to a nabr solution, what would the initial concentration of nabr need to be in order to increase the molar solubility of cd(oh)2 to 1.0×10−3 moles per liter?
Answers: 2
![Cd^{2+} + 4Br^{-}\rightleftharpoons [CdBr_{4}]^{2-} .....Kf =5*10^{3}](/tpl/images/0156/0621/b20e2.png)
-----(1)
---(2)![Cd(OH)_{2} + 4Br^{-}\rightleftharpoons [CdBr_{4}]^{2-}+2OH^{-}](/tpl/images/0156/0621/e6b8f.png)
![K = K_{f}*K_{sp} = 5*10^{3}*2.5*10^{-14}=\frac{[CdBr_{4}^{2-}][OH^{-}]^{2}}{[Br{-}]^{4}}](/tpl/images/0156/0621/29c0f.png)
![12.5*10^{-11} =\frac{1*10^{-3} *[2*10^{-3}]^{2}}{[Br-]^{4} }\\](/tpl/images/0156/0621/ca71c.png)
![[Br-] = 2.38 M](/tpl/images/0156/0621/628e8.png)
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The solubility of cd(oh)2 can be increased through formation of the complex ion cdbr2−4 (kf=5×103)....
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