Calculate the percent ionization of formic acid (hco2h) in a solution that is 0.125 m in formic acid. the ka of formic acid is 1.77 ⋅ 10-4. calculate the percent ionization of formic acid (hco2h) in a solution that is 0.125 m in formic acid. the ka of formic acid is 1.77 10-4. 0.859 0.0180 3.79 2.25 ⋅ 10-5 6.94

Percent ionization of HCOOH is 3.69%

Explanation:

To calculate percent ionization of HCOOH, we have to construct an ICE table to determine changes in concentrations at equilibrium.

    I:                0.125                                       0             0

    C:                -x                                           +x            +x

    E:              0.125-x                                     x              x

species inside third bracket represent equilibrium concentrations

So,      

   or,  

   or,

or, M

So,

Percent ionization of formic acid  = = = 3.69%

i have no clue hope you find the answer

2b2t

explanation:

2b2t