Amixture of three noble gases has a total pressure of 1.25 atm. the individual pressures exerted by neon and argon are 0.68
atm and 0.35 atm, respectively. what is the partial pressure of the third gas, helium?
use py-p+p 2+p3 + +p
o 0.22 am
o 0.33 atm
o 1.03 atm
o 228 atm

0.22 atm

Explanation:

The total pressure is the sum of the partial pressures.

P = P₁ + P₂ + P₃

1.25 atm = 0.68 atm + 0.35 atm + P

P = 0.22 atm

0.22 atm

Explanation:

First, you need to add up each of the values of the known gases

0.68+0.35

Then you need to subtract that value from the total pressure to find the partial pressure of the third value

1.25-(0.68+0.35)

By doing that you get the answer of 0.22 atm

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole