Chemistry, 30.07.2019 06:10 Lalagrl

Calculate the pressure exerted by 0.5000 mol of n2 in a 1.-l container at 25.08c a. using the ideal gas law. b. using the van der waals equation. c. compare the results.

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Answer from: dragonslayer321

Explanation:

a). According to ideal gas equation, product of pressure and volume is equal to the product of number of moles, gas constant and temperature.

Mathematically, PV = nRT

Since, it is given that number of moles is 0.5 mol, volume is 1.0 L and temperature is $25.08^{o}C$ . Or in kelvin temperature will be (25.08 + 273) K = 298.08 K.

Therefore, to calculate the pressure put the given vaues in the ideal gas equation as follows.

PV = nRT

$P \times 1.0 L$ = 0.5 mol \times 0.0821 L atm/mol K \times 298.08 K[/tex]

P = 12.236 atm

= 12.24 atm (approx)

b). Vander waal equation is as follows.

$[P + a (\frac{n}{V})^{2}] (\frac{V}{n} - b)$ = RT

For nitrogen gas, value of a is 1.370 and b is 0.0387. Therefore, putting the given values into Vander waal's equation as follows.

$[P + a (\frac{n}{V})^{2}] (\frac{V}{n} - b)$ = RT

P = $\frac{nRT}{(V - nb)} - \frac{n^{2}a}{V^{2}}$

P = $\frac{0.5 mol \times 0.0821 atm L/mol K \times 298.08 K}{(1 L - (0.5 mol \times 0.0387))} - \frac{(0.5)^{2} \times 1.370}{(1 L)^{2}}$

P = 12.14 atm

c). Pressure calculated using ideal gas equation is 12.24 atm. Whereas pressure calculated using Vander waal's equation is 12.14 atm.

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

Answer from: Quest

C) the increase in atmospheric pressure pushes the walls of the balloon outward thus making it is the answer.hope i you.