Air of 97% relative humidity at 1 atm pressure and 3 1 1 k s to be cooled to 291 k, and fed into a plant at a rate of 8.5 m'/s. 2) (a) [12 points] calculate the rate in kg/min at which the water condenses. (b) [13 points] calculate the cooling requirement in tons assuming that the enthalpy of water vapor is that of saturated steam at the same temperature and the enthalpy of dry air (in kj/mol) as a function of temperature (in °c) is given by the equatiqn h 0.029 (t-25) data: saturation vapor pressure of water at 311 k 6.54 x 102 atm saturation vapor pressure of water at 291 k = 2.04 x 10-2 atm enthalpy of saturated steam at 311 k-2570.8 kj/kg enthalpy of saturated steam at 291 k-2534.5 kj/kg enthalpy of liquid water at 291 k-75.5 kj/kg one ton of cooling- 12,660 kj/hr
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Chemistry, 22.06.2019 10:00, winstonbendariovvygn
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