Chemistry, 26.07.2019 05:30 punani

Asolution is made by dissolving 0.0500 mol of hf in 1.00 kg of water. the solution was found to freeze at –0.104 °c. calculate the value of i and estimate the percent ionization of hf in this solution.

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Answer from: raptortrainor2013

0.0500 moles of HF are dissolved in 1.00 kg of water. Molality of solution is moles of solute divided by the kg of solvent. Since the mass of solvent is just 1.00 kg, the molality of the solution will be 0.0500m.

The formula used for depression in freezing point is written as:

$\Delta T_f=imk_f$

ionization

where, i stands for Van't hoff factor, m stands for molality of solution and kf stands for molal freezing point constant for the solvent.

Pure water freezes at zero degree C and the freezing point of the solution is given as -0.104 degree C. It means, $\Delta T$ =0.104 degree C

kf for water is 1.86 degree C/m .

Let's plug in the values in the formula and calculate the value of i.

0.104=i*0.0500*1.86

0.104=i*0.093

$i=\frac{0.104}{0.093}$

i = 1.12

Van't hoff factor and degree of ionization are related to each other as:

$i=1+\alpha (n-1)$

where alpha stands for degree of ionization and n is the number of ions formed from one formula unit of the substance.

The equation for the ionization of HF is:

$HF\rightarrow H^++F^-$

from above equation, the value of n is 2 as two ions are formed.

Let's plug in the values in the formula and calculate the value of alpha.

$1.12=1+\alpha (2-1)$

$1.12=1+\alpha (1)$

$1.12=1+\alpha$

$\alpha =1.12-1$

$\alpha =0.12$

Value of alpha is 0.12 means the percent ionization of HF in the given solution is 12%.

Thus, the correct Answer is: i = 1.12 and percent ionization is 12% .

Find out more information about ionization here:

link

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

Answer from: Quest

if you're asking what comes out, it's steam.

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Asolution is made by dissolving 0.0500 mol of hf in 1.00 kg of water. the solution was found to free...