Balance the equation khco3+ h3po4 arrow k2hpo4+h20 c02.

2KHCO3+ H3PO4 arrow  K2HPO4 + 2 H20 + 2C02

Explanation:

2KHCO3+ H3PO4 arrow  K2HPO4 + 2 H20 + 2C02

Start with the Ks. Don't start on the right. Just balance the Ks on the left. The reason is that the CO3 is going to break down as well.

2KHCO3+ H3PO4 arrow  K2HPO4 +  H20 + C02

Leave the PO4 alone. Now look at the Hs that are on the right. There are 5 on the left. Leave the K2HPO4 alone. If you put a 2 in front of tthe H2O then you have a total of 5 Hs on the right.

2KHCO3+ H3PO4 arrow  K2HPO4 + 2H20 + C02

There are 2 carbons on the left. You need 2 on the right.

2KHCO3+ H3PO4 arrow  K2HPO4 + 2H20 + 2C02

That should do it.

Let's make a table to show balance.

Species      K              H          C         PO4-         O  

Left             2              5           2          1                6 from CO3^(2-)  

Right           2              5           2          1                6 from H2O/CO2

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3