What is the pressure of 0.540 mol of an ideal gas at 35.5 l and 223 k

0.0443 atm

Explanation:

1) Data:

a) n = 0.540 mol

b) V = 35.5 liter

c) T = 223 K

2) Formula:

Ideal gas equation: PV = nRT

Where,

P = pressureV = volumen = number of molesT = absolute temperature (kelvin scale)R = universal gas constant = 0.08203 atm-liter/K-mol

3) Calculations:

Solve for P

      PV = nRT ⇒ P = nRT/V

Substitute and compute:

       P = 0.540 mol × 0.08206 atm-liter/K-mol × 223 K / 35.5 liter

       P = 0.0443 atm (you must use 3 significant figures).

The answer is d because i just took the test

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