Under certain conditions, the equilibrium constant of the reaction below is kc=1.7×10−3. if the reaction begins with a concentration of 0.0546 m for each of sbcl3 and cl2 and a concentration of 0.0 m for sbcl5, what is the equilibrium concentration (in molarity) of cl2? sbcl5(g)↽−−⇀sbcl3(g)+cl2(g)

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

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Hello! mitosis and meiosis are the same, because they are both ways of dividing cells and reproducing cells. they are different in many ways, but the main one is that meiosis splits the number of chromosomes in 1/2, while the number of chromosomes remains the same for mitosis. plus, meiosis has two stage of division, unlike mitosis, where it has only one.