The amount of gas that occupies 60.82 l at 31.0 °c and 367 mm hg is mol.

1.17mole

Explanation:

Given parameters:

Volume of gas = 60.82L or 60.82dm³

Temperature of the gas = 31.0°C or 304K

Pressure on the gas = 367mmHg

To make calculation easier we convert the pressure from mmHg to atm.

           1 atm = 760mmHg

           367mmHg gives atm = 0.48atm

Solution

Assuming ideality, we can find the number of moles of the gas used. The ideal gas law combines Boyle's law, Charles's Law and Avogadro's law. It is expressed below:

                   PV = nRT

P is the pressure

V is the volume

n is the number of moles

R is the gas constant given as 0.082atmdm³mol⁻¹K⁻¹

T is the temperature in kelvin

The unknown is n, which is the number of moles.

Making n the subject of the formula, we have ;

                    n =

      n = = 1.17mole

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.