70 points and will give brainliest
baking soda (nahco3) can be added to a fruit mix solution to create a carbonated drink. an example is a reaction between baking soda and citric acid below.
c6h8o7 + 3nahco3 → na3c6h5o7 + 3h2o + 3co2
citric acid – 192.0 g/mol baking soda – 84.0 g/mol
how many milliliters of a 0.8 m solution of citric acid would be needed to react with 15 grams of baking soda? show your work.

74mL

Explanation:

Given parameters:

Molar mass of citric acid = 192g/mol

Molar mass of baking soda = 84g/mol

Concentration of citric acid  = 0.8M

Mass of baking powder = 15g

Unknown parameters:

Volume of citric acid = ?

Solution

       Equation of the reaction:

            C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Procedure:

                Number of moles =

                Number of moles =   = 0.179mole

             3 moles of baking powder reacted with 1 mole of citric acid

 0.179 moles of baking powder would react with :

          This yields 0.059mole of citric acid

    Volume of citric acid =

Volume of citric acid = = 0.074L

Expressing in mL gives 74mL

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).

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