The reaction between ethyl bromide (c2h5br) and hydroxide ion in ethyl alcohol at 330 k, c2h5br(alc) + oh-(alc) --> c2h5oh(l) + br-(alc), is first order each in ethyl bromide and hydroxide ion. when [c2h5br] is 0.0477 m and [oh-] is 0.100 m, the rate of disappearance of ethyl bromide is 1.7 x 10^-7 m/s.
what is the value of the rate constant?
k=?

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Given: Order with respect to = 1

Order with respect to = 1

Thus rate law is:

k= rate constant

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Given:

Putting in the values we get:

Thus the value of the rate constant is

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

- "the choice that is not an indicator of a chemical change is "state of matter changes". more common than not, chemical reactions produce energy in the form of light or heat. along with energy, they also produce a new substance called the product that could be in any state of matter (solid, gas, or liquid)."