An sample of water with a mass of 123.00 kg is heated from 25 c to 97 c. if the specific heat of water is 1 j-1 kg k-1 then how much energy is required?

The amount of energy required will be 8856 Joules.

Explanation:

To calculate the amount of heat absorbed, we use the equation:

where,

Q = heat absorbed or released

m = Mass of the substance = 123 kg

c = specific heat capacity of water =

= change in temperature =  (change remains the same)

Putting values in above equation, we get:

Hence, the amount of energy required will be 8856 Joules.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)