Which type of bond is present in hydrogen sulfide

A. electronegativity < 1.0

Explanation:

Hydrogen --> electronegativity value is 2.1

Sulfur --> electronegativity value is 2.5

∆E, the electronegativity difference is 2.5 - 2.1 = 0.4

So, It is a non polar covalent bond present in

Examples :  

The electronegative values of H is 2.1

F is 4.0

O is 3.5  

N is 3.0

∆E value of HF Hydrogen bond  is

4.0 - 2.1 = 1.9

∆E value of H2O Hydrogen bond is

3.5 - 2.1 = 1.4

∆E value of NH3 Hydrogen bond is

3.0 - 2.1 = 0.9

∆E value between 0.5 to 1.7 is a polar covalent bond

∆E value btween 0 to 0.4 is a non polar covalent bond

∆E above 1.7 is an ionic bond

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8