Ammonia gas is dissolved in a 1.00 ×10-4m solution of cuso4to give an equilibrium concentration of [nh3] = 1.60 ×10-3m. calculate the equilibrium concentration of cu2+(aq) ions in the solution

Explanation:

Mixing Ammonia gas into a solution of Copper(II) Sulfate will give Ammonium Sulfate and a precipitate of Copper(II) Hydroxide (Cu(OH)₂). The Ksp of Cu(OH)₂ is published => 2.2 x 10⁻²². Such gives a solubility* of the Cu(OH)₂ to be ~1.77 x 10⁻⁷M =>  [Cu⁺²] ~1.77 x 10⁻⁷M and [OH⁻] = 2(1.77 x 10⁻⁷)M = 3.53 x 10⁻⁷M.  The reaction of Ammonium Hydroxide and Copper(II) Sulfate will generate 1 x 10⁻⁴ mole Cu(OH)₂ as a precipitate but only 1.77 x 10⁻⁷ mole of the hydroxide will remain in  1 Liter of solution b/c of extreme limited solubility.

*Solubility of 1:2 ionization ratio salts = CubeRt(Ksp/4).

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