Chemistry, 08.07.2019 23:40 sairaanwar67

For the reaction h2(g) + co2(g) ⇌ h2o(g) + co(g) at 700ºc, kc = 0.534. calculate the number of moles of h2 that are present at equilibrium if a mixture of 0.300 mole of co and 0.300 mole of h2o is heated to 700ºc in a 10.0-l container.

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Answer from: knownperson233

There are 173.3 moles of hydrogen gas in the container.

Explanation:

H_2(g) + CO_2(g) ⇄ H_2O(g) + CO(g) at 700ºC.

Equilibrium constant of the reaction = K_c=0.534

If a mixture of 0.300 mole of CO and 0.300 mole of H_2O is heated to 700ºC.

Concentration of CO= $[H_2O]=\frac{300 mol}{10.0L}=30 M$

Concentration of $H_2O=[H_2O]=\frac{300 mol}{10.0L}=30 M$

H_2O(g) + CO(g) ⇄ H_2(g) + CO_2(g)

t = 0 30 M 30M

at eq'm (30 M -x) (30 M -x) x x

Equilibrium constant of the reaction = $K_c'=\frac{1}{0.534}=1.872$

$K_c'=\frac{[H_2][CO_2]}{[CO][H_2O]}$

$1.872=\frac{x\times x}{(30 M-x)\times (30 M- x)}$

x = 17.33 M = [H_2]

Moles of hydrogen gas $=x\times 10L =17.33mol/L \times 10L = 173.3 mol$

There are 173.3 moles of hydrogen gas in the container.

Answer from: kelisedudleybroxxsx9

$[H_2]_{eq}=0.0173M$

Explanation:

Hello,

In this case, for the given reaction, the law of mass action turns out:

$Kc=\frac{[H_2O][CO]}{[H_2][CO_2]}$

In such a way, the reactants initial concentrations are:

$[CO_2]_0=[H_2]_0=\frac{0.300mol}{10.0L} =0.030M$

And considering the change due to the equilibrium, the law of mass action takes the following form:

$Kc=\frac{(x)(x)}{(0.030M-x)(0.030M-x)} =\frac{x^2}{0.0009-0.06x+x^2} \\Kc(0.0009-0.06x+x^2)=x^2\\0.0004806-0.03204x+0.534x^2-x^2=0\\0.466x^2+0.03204x-0.0004806=0\\x_1=-0.0814M\\x_2=0.0127M$

The feasible answer is x=0.0127M

Therefore, the hydrogen moles at equilibrium are:

$[H_2]_{eq}=0.030M-0.0127M=0.0173M$

Best regards.

Answer from: Quest

7is b8 is d9 is c10 is a11 is d

Answer from: Quest

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different. let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones). now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first. for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours. so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.