Benzene (c6h6) is a common solvent. the boiling point of the liquid is 80.1 oc at atmospheric pressure. c6h6 (l) → c6h6 (g) what are the changes in free energy (δgo ), enthalpy (δho ), and entropy (δso ) for the process carried out at 80.1o c. what are the changes in free energy (δgo ),

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

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indium, and thallium have three electrons i think

la respuesta es si te gusta hacer lo que siempre haces cuando nunca ves a alguien en el espejo porque sabes que no siempre están ahí.