Determine the amount of heat (in kj) given off when 1.26 × 104 g of ammonia are produced according to the equation n2(g) + 3h2(g) ⟶ 2nh3(g) δh°rxn = −92.6 kj/mol assume that the reaction takes place under standardstate conditions at 25°c.

The enthalpy of the reaction for given amount of ammonia will be -3431.3 kJ.

Explanation:

To calculate the number of moles, we use the equation:

For ammonia:

Given mass of ammonia =

Molar mass of ammonia = 17 g/mol

Putting values in above equation, we get:

We are given:

Moles of ammonia = 74.11 moles

For the given chemical reaction:

By Stoichiometry of the reaction:

If 2 moles of ammonia produces -92.6 kJ of energy.

Then, 74.11 moles of ammonia will produce = of energy.

Thus, the enthalpy of the reaction for given amount of ammonia will be -3431.3 kJ.