Acylinder with a movable piston contains 2.00 g of helium, he, at room temperature. more helium was added to the cylinder and the volume was adjusted so that the gas pressure remained the same. how many grams of helium were added to the cylinder if the volume was changed from 2.00 l to 4.50 l ? (the temperature was held constant.)

2.5 grams

Explanation:

To calculate the moles, we use the equation:

Avogadro's Law: This law states that volume is directly proportional to the number of moles of the gas at constant pressure and temperature.

  (At constant temperature and pressure)  

where,

= initial volume of gas = 2.00 L

= final volume of gas = 4.50 L

= initial number of moles = 0.5 moles

= final number of moles = ?

Now put all the given values in the above equation, we get the final pressure of gas.

Thus moles of helium added to the cylinder = (1.125-0.5)= 0.625 moles

Mass of helium added =

2.5 grams of helium were added to the cylinder if the volume was changed from 2.00 L to 4.50 L.

possibly, yes.

explanation:

the amount of sugar you take in is dangerously high, risk of heart disease, high risk of diabetes, and etc.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer