How much heat will be absorbed by a 55.5 g piece of aluminum (specific heat 0.930 j/g.°c) as it changes temperature from 23.0°c to 67.0°c? kj

The amount of heat absorbed by aluminium is 2.271 kJ.

Explanation:

To calculate the amount of heat absorbed or released, we use the equation:

Q = heat absorbed  = ?

m = mass of aluminium = 55.5 g

c = specific heat capacity of aluminium = 0.930 J/g ° C      

Putting values in above equation, we get:

Q = 2271.06 Joules

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 2271.06 J will be equal to 2.271 kJ

Hence, the amount of heat absorbed by aluminium is 2.271 kJ.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.