What is the ph of 0.001 m h, so4 (strong acid)? after mixing 250 ml 0.001 m h, so, with 750 ml water, what is the ph now?

Answer : The pH of 0.001 M is, 2.69 and the pH after mixing the solution is, 3.30.

Explanation :

First we have to calculate the concentration of hydrogen ion.

The balanced dissociation reaction will be,

The concentration of = x = 0.001 M

The concentration of ion = 2x = 2 × 0.001 M = 0.002 M

The concentration of = x = 0.001 M

Now we have to calculate the pH of 0.001 M .

Now we have to calculate the molarity after mixing the solution.

where,

= molarity of solution = 0.001 M

= volume of solution = 250 ml

= molarity of after mixing = ?

= volume of after mixing = 250 + 750 = 1000 ml

Now put all the given values in the above formula, we get the molarity after mixing the solution.

The concentration of ion =

Now we have to calculate the pH after mixing the solution.

Therefore, the pH of 0.001 M is, 2.69 and the pH after mixing the solution is, 3.30.

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne

2b2t

explanation:

2b2t