You have 3.00 l of a 3.00 m solution of nacl(aq) called solution a. you also have 2.00 l of a 2.00 m solution of agno3(aq) called solution b. you mix these solutions together, making solution c. hint: agcl is a precipitate. calculate the concentrations (in m) of the following ions in solution c. no3-

The concentration of nitrate ions in solution is 0.8 M.

Explanation:

In solution A;

Moles of sodium chloride in solution:

Moles of sodium chloride = 9 mole

In solution B;

Moles of sodium chloride in solution:

Moles of sodium chloride = 4 mole

In solution C;

1 mol of silver chloride reacts with 1 mol of sodium chloride to give 1 mol of silver chloride and 1 mol of sodium nitrate.

Then 4 mol silver chloride reacts with 4 mol of sodium chloride to give 4 mol of silver chloride and 4 mol of sodium nitrate.

1 mol silver nitrate gives 1 mol of nitrate ions.

So, 4 moles of silver nitrate will gives 4 mole of nitrate.

Total volume of solution = 3.00 L+ 2.00 L = 5.00 L

Concentration of nitrate ions in solution:

The concentration of nitrate ions in solution is 0.8 M.

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.