The combustion of titanium with oxygen produces titanium dioxide:
ti (s) + o2 (g) → tio2 (s)
when 2.060 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °c to 91.60 °c. in a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kj/k. the heat of reaction for the combustion of a mole of ti in this calorimeter is kj/mol.
ti = 47.867 amu
o2 = 31.9988 amu
tio2 = 79.8650 amu
report answer in scientific notation use en rather than x 10n

The heat of reaction for the combustion of a mole of Ti in this calorimeter is .

Explanation:

Moles of titanium =

Heat absorbed by the bomb caloriometer on combustion of 0.04303 mol of titanium be Q

The heat capacity of the bomb caloriometer  =c = 9.84 kJ/K

Change in temperature of the bomb caloriometer :

=ΔT=91.60 °C-25.00 °C=66.6 °C = 339.75 K

Q = c × ΔT

3,343.14 kJ of heat energy was released when 0.04303 moles of titanium undergone combustion.

So for 1 mol of titanium:

The heat of reaction for the combustion of a mole of Ti in this calorimeter is .

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )