Chemistry, 01.07.2019 00:10 lazerlemon500

(need all boxes answered)
bicarbonate of soda (sodium hydrogen carbonate) is used in many commercial preparations. its formula is nahco3. find the mass percentages (mass %) of na, h, c, and o in sodium hydrogen carbonate. you may use whole numbers for the masses.
the mass of one mole of nahco3 is:

(need all boxes answered) bicarbonate of soda (sodium hydrogen carbonate) is used in many comm

Answers: 3

Show answers

Answers

Answer from: yeet1273

Answer & Explanation:

If we have 1.0 mol of NaHCO₃:

∴ The mass of 1.0 mol of NaHCO₃ = (no. of moles of NaHCO₃)(the molecular mass of NaHCO₃)

∴ The mass of 1.0 mol of NaHCO₃ = (1)(the molecular mass of NaHCO₃) = (the molecular mass of NaHCO₃).

∴ The mass of 1.0 mol of NaHCO₃ = (atomic weight of Na) + (atomic weight of H) + (atomic weight of C) + 3(atomic weight of O) = (23.0 g of Na) + (1.0 g of H) + (12.0 g of C) + 3(16.0 g of O) = (23.0 g of Na) + (1.0 g of H) + (12.0 g of C) + (48.0 g of O) = 84.0 g.

To find the mass% of each element:

For Na:

The mass% of Na = (the mass of Na)/(the mass of NaHCO₃) = (23.0 g)/(84.0 g) x 100 = 27.381%.

For H:

The mass% of H = (the mass of H)/(the mass of NaHCO₃) = (1.0 g)/(84.0 g) x 100 = 1.19%.

For C:

The mass% of C = (the mass of C)/(the mass of NaHCO₃) = (12.0 g)/(84.0 g) x 100 = 14.285%.

For O:

The mass% of O = (the mass of O)/(the mass of NaHCO₃) = (48.0 g)/(84.0 g) x 100 = 57.143%.

The sum of % of elements = mass% of Na + mass% of H + mass% of C + mass% of O = 27.381% + 1.19% + 14.285% + 57.143% = 99.999% ≅ 100.0%.

Answer from: angelinad02

Here's what I get.

Explanation:

$\text{The mass of one mole of NaHCO$_{3}$ is:}\\\\\text{$\boxed{23}$ g Na +$\boxed{1}$ g H + $\boxed{12}$ g C + $\boxed{48}$ g O = $\boxed{84}$ g}$

$\text{mass $\%$ Na = $\boxed{23}$ g $/$ $\boxed{84}$ g $\times$ 100 = $\boxed{27.38}$ $\%$}\\\\\text{mass $\%$ H = $ \quad \boxed{1}$ g $/$ $\boxed{84}$ g $\times$ 100 = $\boxed{1.19}$ $\%$}\\\\\text{mass $\%$ C = $\:\: \boxed{12}$ g $/$ $\boxed{84}$ g $\times$ 100 = $\boxed{14.29}$ $\%$}\\\\\text{mass $\%$ O = $\:\: \boxed{48}$ g $/$ $\boxed{84}$ g $\times$ 100 = $\boxed{57.14}$ $\%$}$

$\boxed{27.38} + \boxed{1.19} + \boxed{14.29} + \boxed{ 57.14} = \boxed{100.00}$

Answer from: Quest

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

Answer from: Quest

explanation:

0.07 g/cm³

1.37 g/cm³