If 112 g of iron (fe) combines with 24 g of oxygen (o2) how much iron oxide is formed

There are three different oxides of iron: FeO, Fe2O3 (hematite), and Fe3O4 (magnetite). Assuming that the iron oxide formed in this problem is Fe2O3, which is the most common form of iron oxide, the calculations are as follows:

Balanced chemical equation:
        4Fe + 3O2 --> 2Fe2O3
i         2       0.75            0
c        1       0.75           0.5
e        1         0              0.5

Moles Fe = 112g /55.845 = 2
Moles O2 = 24/32 = 0.75

The reaction, with an excess of 1 mol Fe, produced 0.5 moles or 0.5 moles(159.69g/mol) = 79.845 grams of Fe2O3.

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.