Some hydrogen gas is enclosed within a chamber being held at 200∘c with a volume of 0.0250 m3. the chamber is fitted with a movable piston. initially, the pressure in the gas is 1.50×106pa (14.8 atm). the piston is slowly extracted until the pressure in the gas falls to 0.950×106pa. what is the final volume v2 of the container

0.04 m³.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(P₁V₁) = (P₂V₂).

V₁ = 0.025 m³, P₁ = 1.5 x 10⁶ Pa,

V₂ = ??? m³, P₂ = 0.95 x 10⁶ Pa.

∴ V₂ = (P₁V₁)/(P₂) = (0.025 m³)(1.5 x 10⁶ Pa)/(0.95 x 10⁶ Pa) = 0.04 m³.

i think it is true since you can test the answer and can use observations to complete it.