The equilibrium constant is given for two of the reactions below. determine the value of the missing equilibrium constant. 2a(g) + b(g) ⇌ a2b(g) kc = ? a2b(g) + b(g) ⇌ a2b2(g) kc = 16.4 2a(g) + 2b(g) ⇌ a2b2(g) kc = 28.2

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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it is stable as it is in group 0 which have full outer shells of electrons