Cumulative problem. consider the following balanced chemical reaction. how many liters of bromine gas (bra) at 300 c and 735 torr are formed when 275 g of sodium bromide reacts with 176 g of sodium bromate (nabro)? (hint! find your limiting 5 nabr(aq)+ nabro,(aq)+3 h, so(aq)3 bralg)+3 na, sos(aq)+3 hou)

78.87 liters of bromine gas at 300 °C and 735 Torr are formed.

Explanation:

Moles of sodium bromide =

Moles of sodium bromate =

According to reaction , 1 mol of sodium bromate  reacts with 5 moles of sodium bromide.  Then 1.1655 mol of sodium bromate will react with:

of sodium bromide.

This means that sodium bromide is in limiting amount the amount of  bromine gas depends upon sodium bromide.

According to reaction 5 moles of sodium bromide gives 3 moles of bromine gas.

Then 2.6699 moles of sodium bromide will give:

of bromine gas

Volume occupied by bromine gas at 300 °C and 735 Torr.

Pressure of the gas = P =735 Torr = 0.9555 atm

Temperature of the gas = T = 300°C = 573 K

n = 1.60194 mol

V = 78.87 L

78.87 liters of bromine gas at 300 °C and 735 Torr are formed.

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