Consider the following reaction: 2na 2hci > 2n»c1 + h2 how many mols of hydrogen gas (h2) can be produced if you begin with 13.08 grams of each reactant?

The moles of hydrogen gas that can be formed are 0.18 moles.

Explanation:

To calculate the number of moles, we use the equation:

  ....(1)

Given mass of sodium metal = 13.08 g

Molar mass of sodium metal = 23 g/mol

Putting values in above equation, we get:  

Given mass of hydrochloric acid = 13.08 g

Molar mass of hydrochloric acid = 36.5 g/mol

Putting values in above equation, we get:  

For the given chemical equation:

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 2 moles of sodium metal.

So, 0.36 moles of hydrochloric acid will react with = of sodium metal.

As, given amount of sodium metal is more than the required amount. Thus, it is considered as an excess reagent.

So, hydrochloric acid is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the above reaction:

2 moles of hydrochloric acid is producing 1 moles of hydrogen gas.

So, 0.36 moles of hydrochloric acid will produce = of hydrogen gas.

Hence,  the moles of hydrogen gas that can be formed are 0.18 moles.