Chemistry, 26.06.2019 16:10 pchisholm100

Aluminum chloride can be formed from its elements:
(i) 2al(s) + 3cl2 (g) ⟶ 2alcl3 (s) δh° = ? use the reactions here to determine the δh° for reaction (i):
(ii) hcl(g) ⟶ hcl(aq) δh(ii) ° = −74.8 kj
(iii) h2 (g) + cl2 (g) ⟶ 2hcl(g) δh(iii) ° = −185 kj
(iv) alcl3 (aq) ⟶ alcl3 (s) δh(iv) ° = +323 kj/mol
(v) 2al(s) + 6hcl(aq) ⟶ 2alcl3 (aq) + 3h2 (g) δh(v) ° = −1049 kj

Answers: 1

Show answers

Other questions on the subject: Chemistry

Chemistry, 22.06.2019 00:00, metatiley

The p sub shell can hold up to 8 electrons in an atom. true or false?

Answers: 1

continue

Chemistry, 22.06.2019 14:30, Kiaraboyd9366

Select all of the statements which are true. electrons are located in shells or orbits around the atom. electrons orbit slowly around the atom. electrons travel in one flat path around the nucleus of an atom. the valence of an atom is determined by the number of electrons in the atom's outermost shell.

Answers: 1

continue

Chemistry, 22.06.2019 21:50, BookandScienceNerd

Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes

Answers: 1

continue

Chemistry, 23.06.2019 03:30, LlayahHarbin

Ahelium balloon contains 16.9 l of helium at stp. how many atoms of helium are in the balloon

Answers: 1

continue

You know the right answer?

Aluminum chloride can be formed from its elements:
(i) 2al(s) + 3cl2 (g) ⟶ 2alcl3 (s) δh° =...