For the decomposition of calcium carbonate, consider the following thermodynamic data (due to variations in thermodynamic values for different sources, be sure to use the given values in calculating your answer.): δh∘rxn 178.5kj/mol δs∘rxn 161.0j/(mol⋅k) calculate the temperature in kelvins above which this reaction is spontaneous.

Answer : The temperature in kelvins is,

Explanation : Given,

= 178.5 KJ/mole = 178500 J/mole

= 161.0 J/mole.K

Gibbs–Helmholtz equation is :

As per question the reaction is spontaneous that means the value of is negative or we can say that the value of is less than zero.

The above expression will be:

Now put all the given values in this expression, we get :

Therefore, the temperature in kelvins is,

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation: