Classify each of these reactions. ba(clo3)2(s)⟶bacl2(s)+3o2(g)ba(clo3 )2(s)⟶bacl2(s)+3o2(g) acid–base neutralization precipitation redox none of the above 2nacl(aq)+k2s(aq)⟶na2s(aq)+2kcl(aq) 2nacl(aq)+k2s(aq)⟶na2s(aq)+2kcl(aq) acid–base neutralization precipitation redox none of the above cao(s)+co2(g)⟶caco3(s)cao(s)+co2(g) ⟶caco3(s) acid–base neutralization precipitation redox none of the above koh(aq)+agno3(aq)⟶kno3(aq)+agoh(s)k oh(aq)+agno3(aq)⟶kno3(aq)+agoh(s) acid–base neutralization precipitation redox none of the above

The reactions below can be classified as:

We will classify the reactions below using one of the following criteria.

Let's classify each of these reactions.

Ba(ClO₃)₂(s) ⟶ BaCl₂(s) + 3 O₂(g)

None of the above. This is a decomposition reaction, in which a compound decomposes into smaller substances.

2 NaCl(aq) + K₂S(aq) ⟶ Na₂S(aq) + 2 KCl(aq)

None of the above. This is a double displacement reaction, in which both compounds exchange their cations and anions.

CaO(s) + CO₂(g) ⟶ CaCO₃(s)

None of the above. This is a synthesis or combination reaction, in which 2 compounds combine to form a bigger one.

KOH(aq) + AgNO₃(aq) ⟶ KNO₃(aq) + AgOH(s)

Precipitation. Solid AgOH is formed.

The reactions below can be classified as:

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Explanation:

Ba(ClO₃)₂ → BaCl₂ + 3O₂

None of the above

This is a decomposition reaction. In this type of reaction, a single reactant produces two or more products.

2NaCl + K₂S → Na₂S + 2KCl

None of the above

This a double replacement reaction in which there is an exchange of ions to form a new compound.

CaO + CO₂ → CaCO₃

None of the above

This is a synthesis or combination reaction in which a single product forms from two or more reactants.

KOH + AgNO₃ → KNO₃ + AgOH

none of the above

This is a double replacement reaction in which exhange of ions occurs.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"